08.11.2012, 11:11 | #1 |
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Malaysia: Using a tree control
Источник: http://axmas.blogspot.com/2012/11/us...e-control.html
============== 1. In the AOT, create a new class named BudgetModelTree with the following code: class BudgetModelTree { FormTreeControl tree; BudgetModelId modelId; } public void new(FormTreeControl _formTreeControl, BudgetModelId _budgetModelId) { tree = _formTreeControl; modelId = _budgetModelId; } public static BudgetModelTree construct(FormTreeControl _formTreeControl, BudgetModelId_budgetModelId = '') { return new BudgetModelTree(_formTreeControl, _budgetModelId); } private TreeItemIdx createNode(TreeItemIdx _parentIdx, BudgetModelId _modelId, RecId _recId) { TreeItemIdx itemIdx; BudgetModel model; BudgetModel submodel; model = BudgetModel::find(HeadingSub::Heading, _modelId); itemIdx = SysFormTreeControl::addTreeItem(tree, _modelId + ' : ' + model.Txt, _parentIdx, _recId, 0,true); if (modelId == _modelId) { tree.select(itemIdx); } while select submodel where submodel.ModelId == _modelId && submodel.Type == HeadingSub::SubModel { this.createNode(itemIdx, submodel.SubModelId, submodel.RecId); } return itemIdx; } public void buildTree() { BudgetModel model; BudgetModel submodel; TreeItemIdx itemIdx; tree.deleteAll(); tree.lock(); while select RecId, ModelId from model where model.Type == HeadingSub::Heading notExists join submodel where submodel.SubModelId == model.ModelId && submodel.Type == HeadingSub::SubModel { itemIdx = this.createNode(FormTreeAdd::Root, model.ModelId, model.RecId); SysFormTreeControl::expandTree(tree, itemIdx); } tree.unLock(true); } 2. In the AOT, open the BudgetModel form's design, expand the Body group, then expand the GridContainer group, and change the following property of the BudgetModel grid control: Property Value Visible No 3. Create a new Tree control right below the BudgetModel grid with the following properties: Property Value Name Tree Width Column width Height Column height Border Single line RowSelect Yes 4. Add the following code to the bottom of the form's class declaration: BudgetModelTree modelTree; 5. Add the following code to the bottom of form's init(): modelTree = BudgetModelTree::construct(Tree); modelTree.buildTree(); 6. Override selectionChanged() on the Tree control with the following code: public void selectionChanged(FormTreeItem _oldItem, FormTreeItem _newItem, FormTreeSelect _how) { BudgetModel model; BudgetModelId modelId; super(_oldItem, _newItem, _how); if (_newItem.data()) { select firstOnly model where model.RecId == _newItem.data(); if (model.Type == HeadingSub::SubModel) { modelId = model.SubModelId; select firstOnly model where model.ModelId == modelId && model.Type == HeadingSub::Heading; } BudgetModel_ds.findRecord(model); BudgetModel_ds.refresh(); } } 7. Override the delete() method on the BudgetModel data source with the following code: public void delete() { super(); if (BudgetModel.RecId) { modelTree.buildTree(); } } 8. Override the delete() method on the SubModel data source with the following code: public void delete() { super(); if (SubModel.RecId) { modelTree.buildTree(); } } 9. Add the following code to the bottom of the write() method on the BudgetModel data source: modelTree.buildTree(); 10. Override the write() method on the SubModel data source and add the following code to its bottom: modelTree.buildTree(); 11. In the AOT, the BudgetModel form should look like the following screenshot: 12. To test the tree control, open Budgeting | Setup | Budget models. Notice how the ledger budget models are presented as a hierarchy: Источник: http://axmas.blogspot.com/2012/11/us...e-control.html
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